Answer:
The flow speed of the gas in the pipeline is 31.57 m/s.
Explanation:
Given;
diameter of the pipeline, d = 0.25 m
radius of the pipeline, r = d/2 = 0.125 m
volumetric flow rate of the gas, Q = 1.55 m³/s
The cross sectional area of the pipeline is given as;
A = πr²
A = π(0.125²)
A = 0.0491 m²
Volumetric flow rate is given by;
Q = Av
Where;
v is the speed of the fluid in the pipeline
v = Q / A
[tex]v = \frac{1.55 \ \frac{m^3}{s} }{0.0491 \ m^2} \\\\v = 31.57 \ m/s\\[/tex]
Therefore, the flow speed of the gas in the pipeline is 31.57 m/s.
