Answer:
117.28 N/m
Explanation:
step one:
given
Period T= 0.367s
mass m= 0.4kg
Required
the spring constant k
Step two:
The expression for the period, mass and spring constant relation is
T=2π√m/k
making k subject of the formula
[tex]T/2 \pi = \sqrt m/k[/tex]
square both sides
[tex](T/2 \pi)^2= m/k[/tex]
[tex]k= m/(T/2 \pi)^2[/tex]
[tex]k=0.4/(0.367/2*3.142)^2[/tex]
[tex]k=0.4/(0.05840)^2[/tex]
[tex]k=0.4/0.0034105\\\\k=117.28 N/m[/tex]
