Answer:
[tex]CH[/tex]
Explanation:
Hello!
In this case, given the percent composition of C and H in acetylene, in order to find its empirical formula we compute moles of C and H assuming those percentages as masses:
[tex]n_C=92.25gC*\frac{1molC}{12.01gC} =7.68molH\\\\n_H=7.75gH*\frac{1molH}{1.01molH}=7.67molH[/tex]
Next, since they have the same number of moles we infer they are in a 1:1 subscript ratio on the empirical formula, where is therefore:
[tex]CH[/tex]
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