Answer:
Al(OH)₃(aq) + 3 HBr(aq) ⇒ AlBr₃(aq) + 3 H₂O(l)
Explanation:
Let's consider the unbalanced equation for the reaction between solid aluminum hydroxide and a solution of hydrobromic acid. This is a neutralization reaction so it forms a salt, aluminum bromide, and water.
Al(OH)₃(aq) + HBr(aq) ⇒ AlBr₃(aq) + H₂O(l)
We start balancing Br atoms by multiplying HBr by 3.
Al(OH)₃(aq) + 3 HBr(aq) ⇒ AlBr₃(aq) + H₂O(l)
To get the balanced equation, we must multiply H₂O by 3 as well.
Al(OH)₃(aq) + 3 HBr(aq) ⇒ AlBr₃(aq) + 3 H₂O(l)
