Answer:
The correct answer is 0.3088 L.
Explanation:
The reaction will be,
Mg + 2 HCl = MgCl2 + H2
The moles can be determined by using the formula,
Moles = Given mass/Molecular mass
Based on the given information, the weight of Mg is 0.0300 g, and the molecular mass of Mg is 24.30 g/mol.
Now putting the values we get,
Moles = 0.300 g/24.30 g/mol = 0.01235 mol
From the reaction, it can be seen that 1 mol of Mg produces 1 mol of H2 gas then 0.01235 mol of Mg will produce 0.1235 mol of H2.
The volume of hydrogen gas produced can be determined by using the gas law equation,
V = nRT/P
Here V is volume in L, P is the pressure in atm, R is the gas constant, which is 0.08206, and T is temperature in Kelvin, 21.8 degree C = 21.8 + 273.15 = 294.95 K.
P = 735.6 torr = 735.6 * 0.00132 atm = 0.9679 atm
V = 0.1235 mol * 0.08206 atm L/mol/K * 294.95 K/0.9679 atm
V = 0.3088 L
Hence, the volume of hydrogen gas produced is 0.3088 L.
