Answer:
[tex]n_{base}=3.90x10^{-3}molNaOH[/tex]
Explanation:
Hello!
In this case, since the sulfuric acid and sodium hydroxide react in a 1:2 mole ratio, given the reaction, we realize they have the following mole ratio at the equivalence point:
[tex]2*n_{acid}=n_{base}[/tex]
Which in terms of concentrations and volumes is:
[tex]2*M_{acid}V_{acid}=n_{base}[/tex]
Thus, we can plug in the volume and concentration of acid to find the moles of base:
[tex]n_{base}=0.04402L*0.0885\frac{mol}{L} \\\\n_{base}=3.90x10^{-3}molNaOH[/tex]
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