Answer:
[tex]a=8.34\ m/s^2[/tex]
Explanation:
Given that,
The mass of a man, m = 60 kg
When the elevator rises, the scale rads 818 N
We need to find the acceleration of the elevator. Let it is a. The equation of motion can be written as :
F - mg = ma
Put g = 9.8 m/s²
[tex]a=\dfrac{F-mg}{m}\\\\a=\dfrac{818-60(9.8)}{60}\\\\=8.34\ m/s^2[/tex]
So, the acceleration of the elevator is [tex]8.34\ m/s^2[/tex]
