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g If 3.7 g of aluminum, Al, reacts completely with O2 to form aluminum oxide, what mass of aluminum oxide would be produced

Respuesta :

Answer:

6.99g

Explanation:

The balanced equation is:

4Al + 3O2 → 2Al2O3

Using this, we can find the mass of the reactant, Aluminum oxide.

Mass of 1 mole of Al: 26.982 g

Mass of 1 mole of Al2O3: 2*26.982 + 3* 15.999 = 101.961 g

So, the mass of aluminum oxide is:

(3.7/26.982)(2/4)(101.961) = 6.99g

But I'm not 100% sure, so please check my work :)

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