Calculate the force between two small charged spheres having charges of 3×10−7 C and 4×10−7 C placed 20 cm apart.

Respuesta :

Answer:

27 . 10^-7 or 27/1000

Explanation:

We use the Coulomb Law

k = Coloumb Constant

q1 and q2 are the charges

d is the distance between the spheres

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Answer:

The force between the charges is 0.027 N

Explanation:

What is force between charges ?

It is Coulomb's law that states the force between two charges is directly proportional to product of charges and inversely proportional to the square of the distance between them.

[tex]F= 9*10^{9} \frac{q_{1}.q_{2} }{r^{2} }[/tex]

[tex]here[/tex] F is force [tex]q_{1}[/tex] and [tex]q_{2}[/tex] are charges and r is distance between charges.

Given data :

  • [tex]q_{1} = 3*10^{-7} C[/tex] , [tex]4*10^{-7} C[/tex], r = 20 Cm or 0.2 m
  • By putting these values in the above formula

[tex]F =[/tex][tex]9*10^{9} .\frac{3*10^{-7}.4*10^{10-7} }{(0.2)^{2} } }[/tex]

[tex]F =[/tex][tex]\frac{108*10^{-5} }{0.04}[/tex]

[tex]F = 27*10^{-3} N[/tex]  or 0.027 N

Hence the force between the given charges is 0.027 N.

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