This question is based on the simple calculation. Therefore, the expression is equivalent to
[tex]\dfrac{1}{3}x +\dfrac{3}{4} +\dfrac{2}{3} x - \dfrac{1}{4} - \dfrac{2}{3}x[/tex] is [tex]\dfrac{1}{3} x+\dfrac{1}{2}[/tex] .
Given:
[tex]\dfrac{1}{3} x+\dfrac{3}{4} +\dfrac{2}{3} x - \dfrac{1}{4} - \dfrac{2}{3}x[/tex]
We need to determined an expression that is equivalent to[tex]\dfrac{1}{3}x +\dfrac{3}{4} +\dfrac{2}{3} x - \dfrac{1}{4} - \dfrac{2}{3}x[/tex]
Now, solve it further as follows:
Separate the like terms , we get,
[tex]\dfrac{1}{3}x +\dfrac{2}{3} x-\dfrac{2}{3} x+\dfrac{3}{4} - \dfrac{1}{4}[/tex]
Thus, further calculated we get,
[tex]\Rightarrow \dfrac{1}{3} x+\dfrac{1}{2}[/tex]
Therefore, the expression is equivalent to
[tex]\dfrac{1}{3}x +\dfrac{3}{4} +\dfrac{2}{3} x - \dfrac{1}{4} - \dfrac{2}{3}x[/tex] is [tex]\dfrac{1}{3} x+\dfrac{1}{2}[/tex] .
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https://brainly.com/question/22501555
