If each tablet of Tum antiacid contains 0.750 g of CaCO₃, 2 tablets contain 0.0150 mol of CaCO₃.
Tum antiacids are made of CaCO₃. If each tablet contains 0.750 g of CaCO₃, the mass of CaCO₃ in 2 tablets is:
2 Tablets × 0.750 g CaCO₃/1 Tablet = 1.50 g CaCO₃
Now, we want to know the moles of CaCO₃ in 1.50 g of CaCO₃. We need its molar mass.
What is the molar mass?
The molar mass is the sum of the total mass in grams of all the atoms that make up a mole of a particular molecule.
The molar mass of CaCO₃ is 100.09 g/mol. The moles in 1.50 g of CaCO₃ are:
1.50 g × 1 mol/100.09 g = 0.0150 mol
If each tablet of Tum antiacid contains 0.750 g of CaCO₃, 2 tablets contain 0.0150 mol of CaCO₃.
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