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A car is driving across a street. It's change in displacement is 50 m. If it started with a velocity of 5 m/s and ended with a velocity of 7 m/s, what must the acceleration have been?

Respuesta :

Answer:

Ew an sao fan. anyway, it's 0.24m/s^2

Explanation:

Use this equation for 1 dimensional motion with constant acceleration:

Xf = Xi + Vi*T + 0.5A*T^2

Xf is 50 m when Xi is 0m

Vi is 5m/s

A is (7m/s-5m/s)/T = 2m/s/T

So,

50m = 0m + 5m/s *T + 0.5*2m/s/T * T^2

50m = 5m/s * T + 1m/s * T

50m = 6m/s * T

T = 8.33s

A is 2m/s/T

A is 2m/s/8.33s

A is 0.24m/s^2

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