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If a pressure cooker is used to increase the pressure of the cooking environment from 101.3 kPa to 191.0 kPa, calculate the temperature of the steam inside the pressure cooker. Remember, under standard conditions the water would boil at a temperature of 373.15K.

Respuesta :

ysabayomi

Answer:

Explanation:

We can solve this using Gay Lussac's law which states that the pressure of a given mass of gas is directly proportional to it's temperature in kelvin. This law can be illustrated using the formula below

P₁/T₁ = P₂/T₂

where P₁ = 101.3 kPa

P₂ = 191.0 kPa

T₁ = 373.15K

T₂ = ?

101.3/373.15 = 191/T₂

cross-multiply

T₂ = 373.15 x 191/101.3

T₂ = 703.57K

The temperature of the steam inside the pressure cooker is 703.57K

pstnonsonjoku

The temperature is  703.6 K.

The pressure of a given mass of gas is directly proportional to its  temperature at constant volume.

P1 = 101.3 kPa

P2 = 191.0 kPa

T1 = 373.15K

T2 = ?

Now;

P1/T1 = P2/T2

P1T2 = P2T1

T2 = P2T1/P1

T2 = 191.0 kPa × 373.15K/101.3 kPa

T2 = 703.6 K

Learn more about pressure of a gas: https://brainly.com/question/2224724

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