contestada

A 65-kg swimmer pushes on the pool wall and accelerates at 6 m/s^2. The friction experienced by the swimmer is 100 N. How many N of force does the swimmer applies a force of

Respuesta :

abidemiokin

Answer:

490N

Explanation:

According Newton's second law!

\sum Force = mass × acceleration

Fm - Ff = ma

Fm is the moving force

Ff s the frictional force = 100N

mass = 65kg

acceleration = 6m/s²

Required

Moving force Fm

Substitute the given force into thr expression and get Fm

Fm -100 = 65(6)

Fm -100 = 390

Fm = 390+100

Fm = 490N

Hence the force that will cause two cart to move is 490N

onyebuchinnaji

The force the swimmer applied when he pushes on the pool wall is 490 N.

The given parameters;

  • mass of the swimmer, m = 65 kg
  • acceleration of the swimmer, a = 6 m/s²
  • frictional force experienced by the swimmer, Fk = 100 N

The force applied by the swimmer is calculated by applying Newton's second law of motion as shown below;

F = ma

∑F = 0

F - Fk = ma

F = Fk + ma

F = 100 + (65 x 6)

F = 490 N

Thus, the force the swimmer applied when he pushes on the pool wall is 490 N.

Learn more here:https://brainly.com/question/19887955

Otras preguntas