Answer:
0.35 is the friction coefficient.
Explanation:
The equation for the friction coefficient is friction coefficient = force/normal force. The force required here is 14N, and the normal force is the weight, 40N. 14/40=0.35.
The coefficient of sliding friction between the block and the table top is 0.35
Given that a smooth wooden 40.0 N block is placed on a smooth wooden table a force of 14.0N is required to keep the block moving at a constant velocity.
The weight of the wooden block will produce a normal reaction N which is equal in magnitude to the weight. That is,
N = mg = 40N
The resultant force applied = ma = 14 N
Since the velocity is constant, acceleration a = 0
Resultant force = F - [tex]F_{r}[/tex]
where
F = force applied = 14 N
[tex]F_{r}[/tex] = Frictional force.
Substituting every parameters into the equation lead to
F - [tex]F_{r}[/tex] = ma
since a = 0, then,
F - [tex]F_{r}[/tex] = 0
F = [tex]F_{r}[/tex]
To calculate the coefficient of sliding friction between the block and the table top, we will make use of the formula
F = μN
Where μ = coefficient of friction.
substitute all necessary parameters into the formula
14 = 40μ
μ = 14/40
μ = 0.35
Therefore, the coefficient of sliding friction between the block and the table top is 0.35
Learn more about friction here: https://brainly.com/question/13821217
