Answer:
[tex]A_2=128.69\ in^2[/tex]
Step-by-step explanation:
The area of a circle varies directly as the square of its radius.
[tex]A=\pi r^2[/tex]
If r₁ = 2in, A₁ = 12.568 in₂, r₂ = 6.4 in, A₂ = ?
ATQ,
[tex]\dfrac{A_1}{A_2}=\dfrac{r_1^2}{r_2^2}\\\\A_2=\dfrac{A_1r_2^2}{r_1^2}\\\\A_2=\dfrac{12.568 \times 6.4^2}{2^2}\\\\=128.69\ in^2[/tex]
So, the new area of the circle is [tex]128.69\ in^2[/tex].
