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09-12-2020
Mathematics

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1) In a bag of red and green sweets, the ratio of red sweets to green sweets is 3:7. If the bag contains 49 green sweets, how many red sweets are there?

Respuesta :

Muscardinus Muscardinus

10-12-2020

Answer:

Red sweets = 21

Step-by-step explanation:

Let there are 3x red sweets and 7x green sweets.

Total no of 49 green sweets.

ATQ,

7x = 49

x = 7

Red sweets = 3x

= 3(7)

= 21

Hence, there are 21 red sweets.

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