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Find the largest three-digit number that can be written in the form 3^m + 2^n, where m and n are positive integers.

Respuesta :

Answer:

985

Step-by-step explanation:

[tex]let\ m=6[/tex]

[tex]3^{6}=729[/tex][tex]999-729=270[/tex]

[tex]2^{8}=256[/tex] and [tex]2^{9}=512[/tex] which would be to big of a number.

[tex]3^{6}+2^{8}=729+256=985[/tex]

Therefore the largest three-digit integer in this system is 985

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