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In a triangle ABC, AC=24 cm, BC=30 cm, and m∠C=40°. Determine the area of the triangle. Round to nearest square centimeter.

Respuesta :

Answer:

The area of the triangle is 231 cm² to the nearest square centimeter

Step-by-step explanation:

We can find the area of a triangle has the lengths of two sides and the measure of the included angle by using the trigonometry

A = [tex]\frac{1}{2}[/tex] × s1 × s2 × sinФ, where

  • s1 and s2 are the two sides of the triangle
  • Ф is the angle included between s1 and s2

In ΔABC

∵ AC = 24 cm

s1 = 24

∵ BC = 30 cm

s2 = 30

∵ m∠C = 40°

Ф = 40°

→ By using the rule of the area above

∵ A = [tex]\frac{1}{2}[/tex] × 24 × 30 × sin(40°)

∴ A = 231.4035395 cm²

→ Round it to the nearest square centimeter

A = 231 cm²

The area of the triangle is 231 cm² to the nearest square centimeter