Answer:
Solving the expression: [tex]\frac{2}{5}K-3\frac{1}{2}K =15[/tex] we get [tex]\mathbf{K=\frac{-150}{31} \ or \ \ K=-4\frac{26}{31} }[/tex]
Step-by-step explanation:
We need to solve the expression: [tex]\frac{2}{5}K-3\frac{1}{2}K =15[/tex] and find value of k
Solving:
[tex]\frac{2}{5}K-3\frac{1}{2}K =15[/tex]
Convert mixed fraction into improper fraction
[tex]\frac{2}{5}K-\frac{7}{2}K =15[/tex]
Taking LCM of 5 and 2 we get 10
[tex]\frac{2*2K-7*5K}{10} =15\\\frac{4K-35K}{10} =15\\\frac{-31K}{10} =15[/tex]
Divide both sides by -31/10
[tex]\frac{-31K}{10}*\frac{-10}{31}=15* \frac{-10}{31}\\K=\frac{-150}{31} \\K=-4\frac{26}{31}[/tex]
So, solving the expression: [tex]\frac{2}{5}K-3\frac{1}{2}K =15[/tex] we get [tex]\mathbf{K=\frac{-150}{31} \ or \ \ K=-4\frac{26}{31} }[/tex]
