A golf player hits a 0.045 kg golf ball that is initially at rest, changing its momentum by 4.2 kg times m/., What is the final speed of the golf ball?

Respuesta :

Answer:

v₂ = 93.33 [m/s]

Explanation:

In order to solve this problem, we must apply the definition of momentum and amount of movement, which can be calculated by means of the following expression.

[tex]P=m*v[/tex]

where:

P = momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

The amount of movement before and after the impact should be analyzed.

[tex](m_{1}*v_{1})+Imp_{1-2}=(m_{1}*v_{2})[/tex]

where:

m₁ = mass of the ball = 0.045 [kg]

v₁ = velocity of the ball before the hit = 0

Imp₁₋₂ = Impulse [kg*m/s]

v₂ = velocity after the hit [m/s]

[tex](0.045*0)+4.2=(0.045*v_{2})\\4.2 = 0.045*v_{2}\\v_{2}= 93.33 [m/s][/tex]