Answer:
Option A
Step-by-step explanation:
[tex]\frac{5-i}{4+3i} *\frac{4-3i}{4-3i} =\frac{20-15i-4i+3i^{2} }{16-9i^{2} }=\frac{20-19i+3(-1)}{16-9(-1)} =\frac{17-19i}{25}=\frac{17}{25}- \frac{19}{25} i[/tex]
