441 g CaCO₃ would have to be decomposed to produce 247 g of CaO
Further explanation
Reaction
Decomposition of CaCO₃
CaCO₃ ⇒ CaO + CO₂
mass CaO = 247 g
mol of CaO(MW=56 g/mol) :
[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{247}{56}\\\\mol=4.41[/tex]
From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :
[tex]\tt \dfrac{1}{1}\times 4.41=4.41[/tex]
mass CaCO₃(MW=100 g/mol) :
[tex]\tt mass=mol\times MW\\\\mass=4.41\times 100\\\\mass=441~g[/tex]
