Given:
The points are (0,3) and (1,-1).
To find:
The equation of line passes through these points.
Solution:
Standard form of a line is
[tex]Ax+By=C[/tex]
We know that, if a line passes through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], then the equation of the line is
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
The line passes through (0,3) and (1,-1), so the equation of the line is
[tex]y-3=\dfrac{-1-3}{1-0}(x-0)[/tex]
[tex]y-3=\dfrac{-4}{1}(x)[/tex]
[tex]y-3=-4x[/tex]
Adding 4x and 3 on both sides, we get
[tex]4x+y=3[/tex]
Therefore, the standard form of the line is [tex]4x+y=3[/tex].
