A scientist is worried about a new disease being spread by mosquitoes in an area. The
scientist captures a random sample of 137 mosquitoes from the area and tests them to find out whether they carry the disease. In this sample, 22 of the mosquitoes were carrying the disease.

Using this information, the scientist uses 100 simulations of additional samples with the
same proportion of disease-carrying mosquitoes from the sample to determine that the
standard deviation for the proportion of mosquitoes carrying the disease is approximately
0.029.

1. Estimate the proportion of mosquitoes in the area that carry the disease, and provide a margin of error. Explain or show your reasoning.

2. Why did the scientist run the simulations to find additional possible proportions of
mosquitoes in the area that carry the disease?

Question

09-12-2020
Mathematics

contestada

A scientist is worried about a new disease being spread by mosquitoes in an area. The
scientist captures a random sample of 137 mosquitoes from the area and tests them to find out whether they carry the disease. In this sample, 22 of the mosquitoes were carrying the disease.

Using this information, the scientist uses 100 simulations of additional samples with the
same proportion of disease-carrying mosquitoes from the sample to determine that the
standard deviation for the proportion of mosquitoes carrying the disease is approximately
0.029.

1. Estimate the proportion of mosquitoes in the area that carry the disease, and provide a margin of error. Explain or show your reasoning.

2. Why did the scientist run the simulations to find additional possible proportions of
mosquitoes in the area that carry the disease?

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oeerivona oeerivona · Answer 1 · 2020-12-14T05:43:06+01:00

Answer:

1. The estimate of the proportion of mosquitoes in the area that carry the disease is approximately 0.1606 or 16.06%

2. To check for accuracy of the of the value of proportion of disease carrying mosquito in the area

Step-by-step explanation:

The given parameters are;

The number of mosquitoes in the sample = 137

The number of mosquitoes that carry the disease = 22

1. The estimate of the proportion of mosquitoes in the area that carry the disease = (Number of mosquitoes with the disease)/(The number of mosquitoes in the sample)

The estimate of the proportion of mosquitoes in the area that carry the disease = 22/137 ≈ 0.1606 or 16.06%

2. The reason the scientist run the simulations to find additional possible proportions of mosquitoes in the area that carry the disease is to check for variability and accuracy of the proportion of disease carrying mosquito in the area.

poojatomarb76 poojatomarb76 · Answer 2 · 2022-06-07T13:12:39+02:00

1. The proportion of mosquitoes in the region that carry the illness is estimated to be 16.06%.

2. To ensure that the proportion of disease-carrying mosquitos in the region is accurate.

What is the difference between a ratio and a proportion?

A ratio is an ordered pair of integers a and b expressed as a/b, with b never equaling 0. A percentage is a mathematical expression in which two ratios are specified to be equal.

Given data;

There were 137 mosquitos in the sample,[tex]\rm N_s[/tex]

The number of disease-carrying mosquitos is,[tex]\rm N_m[/tex]=22

The estimated proportion of disease-carrying mosquitos in the region is found as;

[tex]\rm D_m=\frac{N_m}{N_s} \\\\ \rm D_m=\frac{22}{137} \\\\ D_m=16.06 \ %[/tex]

2. The scientists used simulations to determine alternative probable proportions of disease-carrying mosquitos in the region in order to check for variability and accuracy in the proportion of disease-carrying mosquitos in the area.

Hence,the proportion of mosquitoes in the region that carry the illness is estimated to be 16.06%.

To learn more about the ratio, refer to the link;

https://brainly.com/question/14335762

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