Respuesta :
The temperature of the 20 L tank containing 68 g of carbon dioxide, CO₂ at 500 KPa is 778.5 K
How to determine the mole of CO₂
- Mass of CO₂ = 68 g
- Molar mass of CO₂ = 44 g/mol
- Mole of CO₂ =?
Mole = mass / molar mass
Mole of CO₂ = 68 / 44
Mole of CO₂ = 1.545 moles
How to determine the temperature
- Volume (V) = 20 L
- Number of mole (n) = 1.545 moles
- Pressure (P) = 500 KPa
- Gas constant (R) = 8.314 LKPa/Kmol
- Temperature (T) =?
Using the ideal gas equation, the temperature of the gas can be obtained as follow:
PV = nRT
Divide both side by nR
T = PV / nR
T = (500 × 20) / (1.545 × 8.314)
T = 778.5 K
Thus, the temperature of the tank is 778.5 K
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