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Guys please help me I have a final exam

a 20.0 l tank of co2 contains 68.0 grams of gas at 500.0 kpa of pressure what is the temperature of the tank ?

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Explanation:

ok that is ans k............

Ver imagen Aaryan7009

The temperature of the 20 L tank containing 68 g of carbon dioxide, CO₂ at 500 KPa is 778.5 K

How to determine the mole of CO₂

  • Mass of CO₂ = 68 g
  • Molar mass of CO₂ = 44 g/mol
  • Mole of CO₂ =?

Mole = mass / molar mass

Mole of CO₂ = 68 / 44

Mole of CO₂ = 1.545 moles

How to determine the temperature

  • Volume (V) = 20 L
  • Number of mole (n) = 1.545 moles  
  • Pressure (P) = 500 KPa
  • Gas constant (R) = 8.314 LKPa/Kmol
  • Temperature (T) =?

Using the ideal gas equation, the temperature of the gas can be obtained as follow:

PV = nRT

Divide both side by nR

T = PV / nR

T = (500 × 20) / (1.545 × 8.314)

T = 778.5 K

Thus, the temperature of the tank is 778.5 K

Learn more about ideal gas equation:

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