Answer:
option D
Step-by-step explanation:
In the right angled triangle , one vertex angle is 60° . The other vertex angle will be = 180 - (90+60) = 30°
Hypotenuse = m ; Perpendicular = n ; Base = 4
Side opposite to 60° = Base
Side adjacent to 60° = Perpendicular
Side opposite to 30° = Perpendicular
Side adjacent to 30° = Base
So,
[tex] \sin(60) = \frac{opposite}{hypotenuse} = \frac{4}{m} [/tex]
[tex] = > \frac{ \sqrt{3} }{2} = \frac{4}{m} [/tex]
[tex] = > m = \frac{4 \times 2}{ \sqrt{3} } = \frac{8}{ \sqrt{3} } [/tex]
Rationalising the value of m gives [tex] \frac{8 \sqrt{3} }{3} [/tex]
Also,
[tex] \tan(30) = \frac{opposite}{adjacent} = \frac{n}{4} [/tex]
[tex] = > \frac{1}{ \sqrt{3} } = \frac{n}{4} [/tex]
[tex] = > n = \frac{4}{ \sqrt{3} } [/tex]
Rationalising the value of n gives [tex] \frac{4 \sqrt{3} }{3} [/tex]
