Answer:
[tex]\boxed{x_1 = \frac{2}{3} ~~or~~x_2 = 1}[/tex]
.
Step-by-step explanation:
[tex](3x - 2)(5x - 4) = (3x - 2)^2[/tex]
[tex]15x^2 - 12x - 10x + 8 = 9x^2 - 12x + 4[/tex]
[tex]15x^2 - 22x + 8 - 9x^2 + 12x - 4 = 0[/tex]
[tex]6x^2 - 10x + 4 = 0[/tex] → divide both segment by 2
[tex]3x^2 - 5x + 2 = 0[/tex]
[tex](3x - 2)(x - 1) = 0[/tex]
[tex]3x - 2 = 0[/tex]
[tex]3x = 2[/tex]
[tex]x = \frac{2}{3}[/tex]
.
[tex]x - 1 =0[/tex]
[tex]x = 1[/tex]
