Respuesta :

We can solve this in 2 ways
Since a1 = 4
a2 = 4 * (3) = 12 i.e( a1* common ratio)
a3 = 12 * (3) = 36 i.e( a2 * common ratio)
a4 = 36 * (3) = 108 i.e( a3* common ratio)
a5 = 108 * (3) = 324 i.e(a4*common ratio)

and so on

The fifth term is 162 in the geometric sequence.

What is geometric sequence?

The geometric sequence defined as a series represents the sum of the terms in a finite or infinite geometric sequence. The successive terms in this series share a common ratio.

The nth term of a geometric progression is expressed as

Tₙ = arⁿ⁻¹

Where a is the first term, r is the common ratio

What is arithmetic sequence?

A arithmetic sequence is defined as an arrangement of numbers which is particular order.

The formula to find the general term of an arithmetic sequence is,

aₙ = a₁ + (n-1)d

Given data :

First term of sequence geometric (a₁) = 2

The common ratio of geometric (r) = 3

To determine the fifth term of geometric sequence

Let the fifth term of sequence = a₅    

The nth term of a geometric sequence is expressed as :

Tₙ = a₁rⁿ⁻¹

Substitute the values of n = 5, a₁ =2 and r = 3 in the formula,

T₅  = (2)(3)⁵⁻¹  

T₅  = (2)(3)⁴

T₅  = (2)(81)

T₅  = 162

Hence, the fifth term is 162 in the geometric sequence

Learn more about geometric sequence here :

https://brainly.com/question/11266123

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