if abcd is dilated by a factor of 1/3 the coordinate of A would be?

Answer:
A' = (-1, -1)
Step-by-step explanation:
Rule for the dilation of any point A(x, y) about the origin by a factor of k is given by the rule,
A(x, y) → A'(kx, ky)
From the graph attached,
Coordinates of point A are (-3, -3) and it is dilated by a scale factor of [tex]\frac{1}{3}[/tex] about the origin then the coordinates of the image point A' will be,
A(-3, -3) → [tex]A'(-3\times \frac{1}{3},-3\times \frac{1}{3})[/tex]
→ A'(-1. -1)
Therefore, coordinates of A' = (-1, -1) is the answer.