Given:
The measurement of the angles of a triangle are 3b,2b,and 4b.
To find:
The smallest angle.
Solution:
According to the angle sum property, the sum of all angles of a triangle is 180 degrees.
[tex]3b+2b+4b=180^{\circ}[/tex] [Angle sum property]
[tex]9b=180^{\circ}[/tex]
Divide both sides by 9.
[tex]b=20^{\circ}[/tex]
Now,
[tex]3b=3(20^{\circ})=60^{\circ}[/tex]
[tex]2b=2(20^{\circ})=40^{\circ}[/tex]
[tex]3b=4(20^{\circ})=80^{\circ}[/tex]
Therefore, the smallest angle is 40 degrees.
