Respuesta :

ujalakhan18

Answer:

[tex]\huge\boxed{\sf t = 4}[/tex]

Step-by-step explanation:

[tex]\sf 3(t+3)+5(3+2t)-76 = 0\\\\Expanding \ Parenthesis\\\\3t + 9 + 15 + 10t -76 = 0\\\\13t + 24 -76 = 0\\\\13t - 52 = 0\\\\Add \ 52 \ to \ both \ sides\\\\13t = 52\\\\Dividing\ both\ sides\ by\ 13\\\\t = 52/13\\\\t = 4\\\\\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807
Expand the brackets
—That’ll be 3t + 9 + 15 + 10t - 76 = 0
Then we rearrange
3t + 10t = 13t
15+9-76 = - 52

Therefore , it’ll be 13t - 52 = 0
Take “-52” to the other side then it’ll turn to “ +52”

13t = 52

Divide both sides by 13

13t/13 = 52/13

T = 4

Simple

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