Your answer will be D.
So, you have the angles 12, 9, 6, and 3. You may see that the place that 6 is makes this a non perfect square. When you have this problem simply add the number on top of it with the number that makes this problem.
For instance...
[tex]\boxed{6+3=9}[/tex]
So, when finding area you must multiply the 2 lengths with each other.
So here our bottom length is also 12. Thus, we must multiply 9 and 12 together.
For instance...
[tex]\boxed{9*12=108}[/tex]
