The given polynomial is divisible by x+3 because f(-3)=0
So , the remainder is equal to 0
Her conclusion is correct.
Given :
Angie divides the polynomial function
[tex]f (x)=x^3+3x^2-7x-21[/tex] by (x+3)
Apply remainder theorem to check whether the remainder is equal to 0
If a polynomial p(x) is divisible by (x-a), the remainder obtained is P(a)
x+3 is the divisor
Lets set the divisor =0 and solve for x
[tex]x+3=0\\x=-3[/tex]
Now we plug in -3 for x in given f(x) and see whether f(-3) =0
[tex]f (x)=x^3+3x^2-7x-21\\f (-3)=(-3)^3+3(-3)^2-7(-3)-21\\f(-3)=-27+27+21-21\\f(-3)=0[/tex]
So, f(-3)=0 and hence the remainder is 0
Her conclusion is correct
Learn more : brainly.com/question/19908280
