Answer:
Partial pressure of O = 11.84 atm
Explanation:
To solve the excersise we think in the partial pressure law with mole fraction.
Mole fraction of gas = Partial pressure of gas / Total pressure
We have data of all the mole fractions:
Let's find out the partial pressure of oxygen in the tank. We replace data in the formula:
0.10 = Partial pressure of gas / 118.4 atm
0.10 . 118.4 atm = Partial pressure of gas → 11.84 atm
If we determine all the partial pressures:
0.70 . 118.4 atm = 82.88 atm → Partial pressure N
0.20 . 118.4 atm = 23.68 atm → Partial pressure He
We can determine the partial pressure of the trimix.
Sum of partial pressures of each gas = Total pressure of the mix
11.84 atm + 82.88 atm + 23.68 atm = 118.4 atm
(A way to see, if our operations were ok)
The partial pressure of oxygen in the tank is required.
The partial pressure of the oxygen in the tank is 11.84 atm.
[tex]x_o[/tex] = The mole fraction of oxygen = 10%
[tex]p[/tex] = The total partial pressure in the tank = 118.4 atm
The mole fraction of a gas is equal to the ratio of partial pressure of the gas to the total partial pressure.
[tex]x_o=\dfrac{p_o}{p}\\\Rightarrow p_o=x_op\\\Rightarrow p_o=0.1\times 118.4\\\Rightarrow p_o=11.84\ \text{atm}[/tex]
The partial pressure of the oxygen in the tank is 11.84 atm.
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