The acceleration of the ball when it hits the vertical wall is -1,400 m/s²
The given expression:
velocity of the ball, v = 28 m/s
time of motion of the ball, t = 0.02 s
To find:
The acceleration of the ball is calculated as follows:
[tex]acceleration = \frac{\Delta velocity}{\Delta time} = \frac{Final \ velocity\ - \ initial \ velocity }{time} \\\\final \ velocity \ of \ the \ ball \ when \ it \ hits \ the \ wall = 0\\\\acceleration = \frac{0 - 28}{0.02} \\\\acceleration = - \ 1,400 \ m/s^2[/tex]
Thus, the acceleration of the ball when it hits the vertical wall is -1,400 m/s²
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