Answer:
[tex]V=\dfrac{2}{25}T+22[/tex]
Step-by-step explanation:
It is given that,
At 0 degrees Celsius, the volume of a gas is 22 liters. For each degree the temperature T (in degrees Celsius) increases, the volume V (in liters) of gas increases by 2/25.
If we take a cartesian coordinate, the line passes through (0,22). The slope of the line is 2/25.
The equation of a point-slope form is given by :
[tex]y-y_1=m(x-x_1)\\\\y-22=\dfrac{2}{25}(x-0)\\\\y-22=\dfrac{2x}{25}\\\\y=\dfrac{2x}{25}+22[/tex]
Here, x will be temperature and y will be volume. So,
[tex]V=\dfrac{2}{25}T+22[/tex]
Hence, the equation that represents the volume in terms of the temperature is [tex]V=\dfrac{2}{25}T+22[/tex]
