Answer:
7.35m/s²
Explanation:
From the question we are not told what to find but we can as well find the acceleration of the wagon.
According to newton second law of motion
[tex]\sum F_x = ma_x\\Fm - Ff = ma_x\\Fm - \mu R = ma_x\\Fm- \mu mg = ma_x\\[/tex]
Fm is the moving force = 410N
[tex]\mu[/tex] is the coefficient of friction = 0.18
m is the mass = 45kg
g is the acceleration dur to gravity = 9.8m/s²
a is the acceleration of the wagon
Substitute the given data into the equation ang get ax
[tex]Fm- \mu mg = ma_x\\410 - (0.18)(9.8)(45) = 45a_x\\410 - 79.38 = 45a_x\\330.62 = 45a_x\\a_x = 330.62/45\\a_x = 7.35m/s^2\\[/tex]
Hence the acceleration of the wagon is 7.35m/s²
