The ball spins once around the circle in 0.20 s, meaning it travels a distance equal to its circumference in that time, giving it a linear speed of
v = (2π (0.5 m)) / (0.20 s) = 5π m/s ≈ 15.708 m/s
Use this compute the magnitude of the centripetal acceleration a :
a = v²/ (0.5 m) = 50π² m/s² ≈ 493.48 m/s²
Use Newton's second law to compute the mangitude of the tension F in the string:
F = (0.05 kg) a = 5/2 π² N ≈ 24.674 N ≈ 25 N
