coach purchased footballs and basketballs from two different stores.
Each football costs the same amount, and each basketball costs the same
amount.
At the first store, the coach paid $110 for 5 footballs and 14 basketballs.
At the second store, the coach paid $82.50 for 10 footballs and 6
basketballs.
What was the cost in dollars of each basketball?

Respuesta :

Answer:

  • $6.25

Step-by-step explanation:

Let football cost be f and basketball cost be b

We have two equations as per given:

  • 5f + 14b = 110
  • 10f + 6b = 82.50

We need to find b, therefore we'll eliminate f

To do so we'll double the first equation and subtract the second one:

  • 2(5f + 14b) - (10f + 6b) = 2(110) - 82.50
  • 28b - 6b = 220 - 82.50
  • 22b = 137.5
  • b = 137.5/22
  • b = 6.25

Each basketball costs $6.25

Question:

Coach purchased footballs and basketballs from two different stores.

Each football costs the same amount, and each basketball costs the same amount.

At the first store, the coach paid $110 for 5 footballs and 14 basketballs.

At the second store, the coach paid $82.50 for 10 footballs and 6 basketballs.

What was the cost in dollars of Each basketball?

Answer:

Probably 7


REAL Answer:
6.25

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