Answer: The heat required to melt 25.0 g of ice at [tex]0^0C[/tex] is 8350 Joules
Explanation:
Heat of Fusion tells us how much energy is needed to convert 1g of a solid to a liquid at the same temperature.
[tex]Q=m\times L[/tex]
Q = Heat absorbed = ?
m = mass of ice = 25.0 g
L = Latent heat of fusion of ice = 334 J/g
Putting in the values, we get:
[tex]Q=25.0g\times 334J/g=8350J[/tex]
Thus heat required to melt 25.0 g of ice at [tex]0^0C[/tex] is 8350 Joules
