Answer:
6282 kJ
Explanation:
Given that:
The mass (m) = 15 kg
The specific latent heat of ice fusion [tex]h_{fg}_{ice}[/tex] = 335 kJ/kg
The specific heat capacity of water = 4.19 kJ/kg.c
The initial temperature of the ice [tex]T_i[/tex]= 0° C
The final temperature of the water [tex]T_f[/tex] = 20° C
To find the needed amount of heat to convert 0° C ice to 20° C of water.
To do that, we need to find the latent heat required for the phase change from 0° C ice to 0° C water, then the heat required to convert 0° C water to 20° C water.
Heat required = [tex]m \times h_{fg}_{ice}+ m \times c_{water} \times \Delta T[/tex]
Heat required = (15 × 335) + (15 × 4.19) × (20 - 0)
Heat required = 5025 + 62.85 × 20
Heat required = 5025 + 1257
Heat required = 6282 kJ