Answer:
dₓ = 1.35 m
dy = 1.86 m
Explanation:
In order to find the vertical and horizontal components of the displacement, we can assume a right triangle. Such that, the length of string is the hypotenuse, making and angle of 54° with the base of triangle. The base is the horizontal component of displacement. And the perpendicular is the vertical component of displacement. Therefore:
[tex]d_{x} = d\ Cos\ \theta[/tex]
where,
dₓ = horizontal component of displacement = ?
d = resultant displacement = 2.3 m
θ = angle between displacement and ground = 54°
Therefore,
[tex]d_{x} = (2.3\ m)\ Cos\ 54^0[/tex]
dₓ = 1.35 m
For vertical component of displacement:
[tex]d_{y} = d\ Sin\ \theta\\d_{y} = (2.3\ m)\ Sin\ 54^0[/tex]
dy = 1.86 m
