Answer:
the question is incomplete:
λ = 20
μ₀ = 30
μ₁ = 60
Ls for good weather = 20 / (60 - 20) = 20/40 = 0.5
Ls for bad weather = 20 / (30 - 20) = 20/10 = 2
Ws for good weather = 60 / 40 = 1.5
Ws for bad weather = 60 / 10 = 6
Wg for good weather = 1.5 - (60 / 60) = 1.5 - 1 = 0.5
Wg for bad weather = 6 - (60 / 30) = 6 - 2 = 4
Fuel consumed due to slack:
good weather = Ws x λ = 1.5 x 20 = 30 gallons
bad weather = Ws x λ = 6 x 20 = 120 gallons
So each plane should expect to consume 120 - 30 = 90 additional gallons of fuel due to bad weather