Respuesta :

CintiaSalazar

Answer:

The molar concentration of a solution made with 3.744 g of Mg(NO₃)₂ dissolved in enough water to make 50.0 mL of solution is [tex]0.5 \frac{moles}{L}[/tex]

Explanation:

Molarity or Molar Concentration is the number of moles of solute that are dissolved in a certain volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

[tex]molarity=\frac{number of moles}{volume}[/tex]

In this case:

  • Mg: 24.3 g/mole
  • N: 14 g/mole
  • O: 16 g/mole

So, the molar mass of Mg(NO₃)₂ is:

Mg(NO₃)₂= 24.3 g/mole + 2*(14 g/mole + 3*16 g/mole)= 148.3 g/mole

So, if you have 3.744 g of Mg(NO₃)₂, you can apply the following rule of three: if 148.3 grams of Mg(NO₃)₂ are present in 1 mole, 3.744 grams in how many moles are present?

[tex]moles=\frac{3.744 grams*1mole}{148.3 grams}[/tex]

moles= 0.025

Then you have:

  • number of moles=0.025
  • volume= 50 mL= 0.05 L (being 1,000 mL= 1 L)

Replacing in the definition of molarity:

[tex]molarity=\frac{0.025 moles}{0.05 L}[/tex]

you get:

[tex]molarity=0.5 \frac{moles}{L}[/tex]

The molar concentration of a solution made with 3.744 g of Mg(NO₃)₂ dissolved in enough water to make 50.0 mL of solution is [tex]0.5 \frac{moles}{L}[/tex]

ajeigbeibraheem

The molar concentration of the solution is 0.506 M

The molar concentration of a solution is known as molarity. The molarity of a solution is defined as the moles of a solute per liter of a solution.

It can be expressed as:

[tex]\mathbf{Molarity = \dfrac{moles \ of \ solute}{volume \ of \ the \ solution}}[/tex]

  • The molar mass of magnesium nitrate Mg(NO3)2 = 148.3 g/mol
  • The mass of the solute Mg(NO3)2 = 3.744 g

The relation used in determining the number of moles is:

[tex]\mathbf {number \ of \ moles = \dfrac{mass}{molar \ mass}}[/tex]

[tex]\mathbf {number \ of \ moles = \dfrac{3.744 \ g}{148.3 \ g/mol}}[/tex]

[tex]\mathbf {number \ of \ moles = 0.0253 \ g/mol}[/tex]

∴

[tex]\mathbf{Molarity = \dfrac{moles \ of \ solute}{volume \ of \ the \ solution}}[/tex]

[tex]\mathbf{Molarity = \dfrac{0.0253 \ g/mol}{0.05 \ L}}[/tex]

[tex]\mathbf{Molarity =0.506 \ M}[/tex]

Therefore, we can conclude that the molar concentration of the solution is 0.506 M

Learn more about molar concentration here:

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