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One pipe can empty a tank 2.5 times faster than another pipe. Starting with
a full tank, if both pipes are turned on, it takes 7.5 hours to empty the tank.
How long does it take the faster pipe working alone to empty a full tank?

Respuesta :

Answer:

10.5 hours to empty the tank with the faster pipe

Answer:

pipe will empty the tank in 10.5 hours, working alone.

Step-by-step explanation:

Let x be the rate of work of the slower pipe (measured in the tank volume per hour).

Then the rate of work of the faster pipe is 2.5x of the tank volume per hour.

The combined rate of the two pipes is then  x + 2.5x = 3.5x.

We are given

7.5*3.5*x = 1;  hence   x = 1%2F%287.5%2A3.5%29.

Then  2.5x = 2.5%2F%287.5%2A3.5%29 = 1%2F%283%2A3.5%29 = 1%2F10.5.

It means that the faster pipe will empty the tank in 10.5 hours, working alone.

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