contestada

The value of ΔH° for the reaction below is -126 kJ. __________ kj are released when 2.00 mol of NaOH is formed in the reaction?

2 Na2O2 (s) + 2 H2O (l) → 4NaOH (s) + O2 (g)

A) 252
B) 63
C) 3.9
D) 7.8
E) -126

Respuesta :

Cricetus

"63" kj are released. A further solution is provided below.

The equation is:

  • [tex]2 Na_2O_2 (s) + 2 H_2O (l) \rightarrow 4NaOH (s) + O_2 (g)[/tex]

Value of ΔH,

  • -126 kJ

As we know,

  • 4 moles of NaOH - (-126) kJ  
  • 2 moles of NaOH - X

Now,

→ [tex]4\times X=-126\times 2[/tex]

→     [tex]4X = -252[/tex]

→       [tex]X = -\frac{252}{4}[/tex]

→            [tex]= -63[/tex]

Thus the above response is correct.

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https://brainly.com/question/15367152

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