Answer:
B. [tex]\sqrt{290}[/tex]
Step-by-step explanation:
On Edge, just finished the test.
The correct answer is option B which is the norm of the vector v is √290.
The quantity that needs both the direction and the magnitude for their representation is called a vector.
The norm of vector v will be calculated as:-
Let v be a vector with an initial point (–5, –11) and terminal point (6, 2).
Norm = [tex]\sqrt{(6-(-5))^2+( 2-(-11))^2[/tex]
Norm = [tex]\sqrt{121 + 169\\[/tex]
Norm = [tex]\sqrt { 290[/tex]
Therefore the correct answer is option B which is the norm of the vector v is √290.
To know more about vectors follow
https://brainly.com/question/25705666
#SPJ2
