Answer:
Equation of circle in standard form with centre (0, – 10) and radius 6. [tex]\mathbf{x^2+(y+10)^2=36}[/tex]
Step-by-step explanation:
We need to write equation of circle in standard form with centre (0, – 10) and radius 6.
The equation of circle is: [tex](x-h)^2+(y-k)^2=r^2[/tex]
where (h,k) is centre of circle and r is radius
We are given centre (0,-10) so, h=0, k=-10 and radius r = 6
Putting values and finding equation:
[tex](x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-(-10))^2=(6)^2\\x^2+(y+10)^2=36[/tex]
So, equation of circle in standard form with centre (0, – 10) and radius 6. [tex]\mathbf{x^2+(y+10)^2=36}[/tex]
