Answer:
Solving we get x=4
Option B is correct.
Step-by-step explanation:
We are given:
Perpendicular = x
Hypotenuse = [tex]4\sqrt{2}[/tex]
We need to find value of x.
We know that [tex]sin(\theta)=\frac{Perpendicular}{Hypotenuse}[/tex]
[tex]sin(45^{\circ})=\frac{Perpendicular}{Hypotenuse} \\sin(45^{\circ})=\frac{x}{\sqrt{2}}[/tex]
We know that [tex]sin 45^{\circ} =\frac{1}{\sqrt{2} }[/tex]
Solving:
[tex]\frac{1}{\sqrt{2} } =\frac{x}{4\sqrt{2}}\\x=\frac{4\sqrt{2} }{\sqrt{2} } \\x=4[/tex]
So, solving we get x=4
Option B is correct.
